The patent badge is an abbreviated version of the USPTO patent document. The patent badge does contain a link to the full patent document.

The patent badge is an abbreviated version of the USPTO patent document. The patent badge covers the following: Patent number, Date patent was issued, Date patent was filed, Title of the patent, Applicant, Inventor, Assignee, Attorney firm, Primary examiner, Assistant examiner, CPCs, and Abstract. The patent badge does contain a link to the full patent document (in Adobe Acrobat format, aka pdf). To download or print any patent click here.

Date of Patent:
Feb. 23, 2016

Filed:

Jul. 06, 2005
Applicants:

Jean Beguinot, Le Creusot, FR;

Frédéric Bouchaud, Montchanin, FR;

Jean Pisseloup, Saint Symphorien de Marmagne, FR;

Inventors:

Jean Beguinot, Le Creusot, FR;

Frédéric Bouchaud, Montchanin, FR;

Jean Pisseloup, Saint Symphorien de Marmagne, FR;

Assignee:

INDUSTEEL FRANCE, St Denis, FR;

Attorneys:
Primary Examiner:
Assistant Examiner:
Int. Cl.
CPC ...
C22C 38/22 (2006.01); C22C 38/60 (2006.01); B29C 33/38 (2006.01); C22C 38/00 (2006.01); C22C 38/42 (2006.01); C22C 38/44 (2006.01); C22C 38/46 (2006.01); C22C 38/58 (2006.01); B29C 45/00 (2006.01);
U.S. Cl.
CPC ...
C22C 38/60 (2013.01); B29C 33/38 (2013.01); C22C 38/001 (2013.01); C22C 38/42 (2013.01); C22C 38/44 (2013.01); C22C 38/46 (2013.01); C22C 38/58 (2013.01); B29C 45/00 (2013.01);
Abstract

The invention concerns mold or mold frame parts for plastic material injection molding made of quenched and tempered martensitic stainless steel consisting, in wt. %, of: 0.02%=C=0.09%, 0.025%=N=0.12% with 0.05%=C+N=0.17%; Si=0.34% Al=0.080% with Si+23 Al=0.20% and Si+0.6 Al=0.25%; and 0.00025=Al×N=0.0020 0; 0.55%=Mn=1.8%; 11.5%=Cr=16% optionally up to 0.48% of copper, up to 0.90% of the sum Mo+W/2, up to 0.90% of nickel, up to 0.090% of vanadium, up to 0.090% of niobium, up to 0.025% of titanium, optionally up to 0.25 of sulphur, the rest being iron and impurities derived from preparation, the composition further satisfying the condition: 6.5=F═(Cr+Mo)+2(Si+V+Nb)−27(C+N)−(Ni+Mn/2+Cu/3)=13.


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