The patent badge is an abbreviated version of the USPTO patent document. The patent badge does contain a link to the full patent document.

The patent badge is an abbreviated version of the USPTO patent document. The patent badge covers the following: Patent number, Date patent was issued, Date patent was filed, Title of the patent, Applicant, Inventor, Assignee, Attorney firm, Primary examiner, Assistant examiner, CPCs, and Abstract. The patent badge does contain a link to the full patent document (in Adobe Acrobat format, aka pdf). To download or print any patent click here.

Date of Patent:
Oct. 06, 2015

Filed:

Aug. 07, 2012
Applicants:

Masafumi Miyazaki, Tokyo, JP;

Hideaki Yamamura, Tokyo, JP;

Satoru Mineta, Tokyo, JP;

Inventors:

Masafumi Miyazaki, Tokyo, JP;

Hideaki Yamamura, Tokyo, JP;

Satoru Mineta, Tokyo, JP;

Attorney:
Primary Examiner:
Assistant Examiner:
Int. Cl.
CPC ...
B22D 1/00 (2006.01); B22D 11/00 (2006.01); B22D 11/108 (2006.01); B22D 11/11 (2006.01); C21C 7/06 (2006.01); C21C 7/00 (2006.01); C22C 38/00 (2006.01); C22C 38/14 (2006.01);
U.S. Cl.
CPC ...
B22D 1/00 (2013.01); B22D 11/00 (2013.01); B22D 11/108 (2013.01); B22D 11/11 (2013.01); C21C 7/0006 (2013.01); C21C 7/06 (2013.01); C22C 38/005 (2013.01); C22C 38/14 (2013.01);
Abstract

A low-carbon steel slab producing method includes: adding Ti to a molten steel decarbonized to have a carbon concentration of 0.05 mass % or less, and subsequently adding at least one of La and Ce to adjust a constitution, and producing a smelted molten steel; and pouring the smelted molten steel into a casting mold via a tundish; wherein at least one of La and Ce in a total amount of 0.2 to 1.2 times an increased amount of oxygen in the smelted molten steel during contained in the tundish is added to the smelted molten steel in the tundish, so as to obtain a steel slab having inclusions which contain oxides of Ti and at least one of La and Ce as chief components, and so as to make a composition of each of the inclusions have a mass ratio of 0.1 to 0.7, in terms of (LaO+CeO)÷TiO(n=1˜2).


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