The patent badge is an abbreviated version of the USPTO patent document. The patent badge does contain a link to the full patent document.

The patent badge is an abbreviated version of the USPTO patent document. The patent badge covers the following: Patent number, Date patent was issued, Date patent was filed, Title of the patent, Applicant, Inventor, Assignee, Attorney firm, Primary examiner, Assistant examiner, CPCs, and Abstract. The patent badge does contain a link to the full patent document (in Adobe Acrobat format, aka pdf). To download or print any patent click here.

Date of Patent:
Sep. 23, 2014

Filed:

Mar. 28, 2011
Applicants:

Kazumi Yoshizaki, Suntou-gun, JP;

Shinya Yachi, Mishima, JP;

Yasushi Katsuta, Susono, JP;

Kenichi Nakayama, Numazu, JP;

Takeshi Kaburagi, Suntou-gun, JP;

Inventors:

Kazumi Yoshizaki, Suntou-gun, JP;

Shinya Yachi, Mishima, JP;

Yasushi Katsuta, Susono, JP;

Kenichi Nakayama, Numazu, JP;

Takeshi Kaburagi, Suntou-gun, JP;

Assignee:
Attorney:
Primary Examiner:
Int. Cl.
CPC ...
G03G 9/087 (2006.01); G03G 9/093 (2006.01); G03G 9/08 (2006.01);
U.S. Cl.
CPC ...
G03G 9/0821 (2013.01); G03G 9/09328 (2013.01); G03G 9/08795 (2013.01); G03G 9/09392 (2013.01); G03G 9/08797 (2013.01); G03G 9/09321 (2013.01); G03G 9/09385 (2013.01);
Abstract

A toner is provided which has toner particles and an inorganic fine powder; the toner particles being obtained by suspension polymerization using a specific polar resin. The toner is a toner in which; where, in displacement levels found in a micro-compression test in which a force is applied to a toner single particle at a loading rate of 9.8×10N/sec to measure a displacement level (μm) at a point of time where the force has reached a maximum force of 4.90×10N, the displacement level of the toner at a measurement temperature of 25° C. is represented by X(25) and the displacement level of the toner at a measurement temperature of 50° C. by X(50), and the number average particle diameter of the toner is represented by D (μm), the X(25), X(50) and D satisfies the relations:0.10≦(25)/≦0.35  (1)30≦[(50)−(25)]/(25)×100≦150  (2).


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