The patent badge is an abbreviated version of the USPTO patent document. The patent badge does contain a link to the full patent document.

The patent badge is an abbreviated version of the USPTO patent document. The patent badge covers the following: Patent number, Date patent was issued, Date patent was filed, Title of the patent, Applicant, Inventor, Assignee, Attorney firm, Primary examiner, Assistant examiner, CPCs, and Abstract. The patent badge does contain a link to the full patent document (in Adobe Acrobat format, aka pdf). To download or print any patent click here.

Date of Patent:
Jan. 31, 2006

Filed:

Oct. 05, 2001
Applicants:

Hideki Sakai, Kanagawa, JP;

Yuzuru Fukushima, Miyagi, JP;

Junji Kuyama, Kanagawa, JP;

Mamoru Hosoya, Kanagawa, JP;

Inventors:

Hideki Sakai, Kanagawa, JP;

Yuzuru Fukushima, Miyagi, JP;

Junji Kuyama, Kanagawa, JP;

Mamoru Hosoya, Kanagawa, JP;

Assignee:

Sony Corporation, Tokyo, JP;

Attorney:
Primary Examiner:
Assistant Examiner:
Int. Cl.
CPC ...
H01M 4/00 (2006.01); H01M 6/10 (2006.01); H01M 4/36 (2006.01); H01M 4/52 (2006.01); H01M 4/58 (2006.01);
U.S. Cl.
CPC ...
Abstract

A non-aqueous electrolyte cell having high discharge capacity, an improved capacity upkeep ratio and optimum cyclic characteristics. The non-aqueous electrolyte cell has a cell device including a strip-shaped cathode material and a strip-shaped anode material, layered and together via a separator and coiled a plural number of times, a non-aqueous electrolyte solution, and a cell can for accommodating cell device and the non-aqueous electrolyte solution. The cathode employs a cathode active material containing a compound of the olivinic structure represented by the general formula LiFeMPO, where M is at least one selected from the group consisting of Mn, Cr, Co, Cu, Ni, V, Mo, Ti, Zn, Al, Ga, Mg, B and Nb, with 0.05≦x≦1.2 and 0≦y≦0.8, with the compound being used either singly or in combination with other materials. The ratio of an inner diameter d to an outer diameter D of cell device is selected so that 0.05<d/D<0.5.


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