The patent badge is an abbreviated version of the USPTO patent document. The patent badge does contain a link to the full patent document.

The patent badge is an abbreviated version of the USPTO patent document. The patent badge covers the following: Patent number, Date patent was issued, Date patent was filed, Title of the patent, Applicant, Inventor, Assignee, Attorney firm, Primary examiner, Assistant examiner, CPCs, and Abstract. The patent badge does contain a link to the full patent document (in Adobe Acrobat format, aka pdf). To download or print any patent click here.

Date of Patent:
May. 31, 2022

Filed:

Nov. 27, 2019
Applicant:

Smartdyelivery Gmbh, Jena, DE;

Inventors:

Christoph Englert, Jena, DE;

Marc Lehmann, Jena, DE;

Assignee:
Attorney:
Primary Examiner:
Int. Cl.
CPC ...
B01J 19/18 (2006.01); B01J 19/00 (2006.01);
U.S. Cl.
CPC ...
B01J 19/18 (2013.01); B01J 19/0066 (2013.01); B01J 2219/00765 (2013.01); B01J 2219/00858 (2013.01); B01J 2219/00894 (2013.01); B01J 2219/1943 (2013.01);
Abstract

The invention discloses a reactor for preparing a formulation. The reactor comprises at least two apertures, a base and at least one sidewall extending flush therefrom, wherein the base and the sidewall together define a mixing chamber with a height hand at least one axis of symmetry arranged substantially perpendicular to the base and at least one distance r from the sidewall. A first aperture is arranged within the base or adjacent to the base in the sidewall of the mixing chamber at a height hranging from 0.6 to 0.0 hin order to introduce free-flowing materials and/or mixtures to the mixing chamber. The first aperture is configured with a non-return valve disposed therein or adjacent thereto, the non-return valve permitting the introduction of free-flowing materials to the mixing chamber through the aperture, but preventing outflow of free-flowing materials from the mixing chamber through the aperture. The first aperture is formed with an aperture area extending in a range between a minimum and a maximum, the minimum area being 0.05 mmand the maximum area being determined by a value resulting from Volume[cm]/Area[cm]≈5500.


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