The patent badge is an abbreviated version of the USPTO patent document. The patent badge does contain a link to the full patent document.

The patent badge is an abbreviated version of the USPTO patent document. The patent badge covers the following: Patent number, Date patent was issued, Date patent was filed, Title of the patent, Applicant, Inventor, Assignee, Attorney firm, Primary examiner, Assistant examiner, CPCs, and Abstract. The patent badge does contain a link to the full patent document (in Adobe Acrobat format, aka pdf). To download or print any patent click here.

Date of Patent:
May. 10, 2022

Filed:

Jun. 25, 2018
Applicant:

Toyota Jidosha Kabushiki Kaisha, Toyota, JP;

Inventor:

Mitsuhiro Nada, Toyota, JP;

Assignee:
Attorney:
Primary Examiner:
Int. Cl.
CPC ...
B60K 6/32 (2007.10); H01M 8/24 (2016.01); B60L 50/90 (2019.01); B60L 50/64 (2019.01); B60L 50/72 (2019.01); G06F 30/15 (2020.01); B60L 50/75 (2019.01); B62D 65/00 (2006.01); H01M 8/249 (2016.01); H01M 16/00 (2006.01);
U.S. Cl.
CPC ...
B60K 6/32 (2013.01); B60L 50/64 (2019.02); B60L 50/72 (2019.02); B60L 50/75 (2019.02); B60L 50/90 (2019.02); B62D 65/00 (2013.01); G06F 30/15 (2020.01); H01M 8/249 (2013.01); H01M 16/006 (2013.01); B60L 2200/36 (2013.01); B60L 2240/42 (2013.01); H01M 2220/20 (2013.01); H01M 2250/20 (2013.01);
Abstract

A method of designing a machine on which a drive motor, a fuel cell stack, and a secondary battery are mounted includes: determining a maximum output of the drive motor to be a first output value and an output of the drive motor when a vehicle travels under a cruise condition to be a second output value; determining the number of fuel cell stacks to be mounted to be n; and determining a maximum output of the secondary battery to be a value obtained by subtracting a value obtained by multiplying a maximum output of the fuel cell stack by the n, from the first output value. A value obtained by multiplying the third output value by the n is equal to or larger than the second output value, and a value obtained by multiplying the third output value by (n−1) is less than the second output value.


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